3^2+(-30)=r^2

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Solution for 3^2+(-30)=r^2 equation: 



3^2+(-30)=r^2

We move all terms to the left:

3^2+(-30)-(r^2)=0

We add all the numbers together, and all the variables

-1r^2-21=0

a = -1; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·(-1)·(-21)
Δ = -84
Delta is less than zero, so there is no solution for the equation

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